fix: ユーザー検索で、クエリがusernameの条件を満たす場合はusernameもLIKE検索するように (#8644)
* Fix #8643 * 部分一致にする
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@ -61,7 +61,14 @@ export default define(meta, paramDef, async (ps, me) => {
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.getMany();
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} else {
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const nameQuery = Users.createQueryBuilder('user')
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.where('user.name ILIKE :query', { query: '%' + ps.query + '%' })
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.where(new Brackets(qb => {
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qb.where('user.name ILIKE :query', { query: '%' + ps.query + '%' });
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// Also search username if it qualifies as username
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if (Users.validateLocalUsername(ps.query)) {
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qb.orWhere('user.usernameLower LIKE :username', { username: '%' + ps.query.toLowerCase() + '%' });
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}
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}))
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.andWhere(new Brackets(qb => { qb
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.where('user.updatedAt IS NULL')
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.orWhere('user.updatedAt > :activeThreshold', { activeThreshold: activeThreshold });
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